What will be $C$ in the following reaction?
$C_6H_5CH_3$ $\xrightarrow{\text{Oxidation}} A$ $\xrightarrow{NaOH} B$ $\xrightarrow[\Delta]{\text{sodalime}} C$
$C_6H_5CH_3$ $\xrightarrow{\text{Oxidation}} A$ $\xrightarrow{NaOH} B$ $\xrightarrow[\Delta]{\text{sodalime}} C$
- A$C_6H_5OH$
- B$C_6H_6$
- C$C_6H_5COONa$
- D$C_6H_5ONa$
Explore More
Similar Questions
The product formed when benzene is nitrated by fuming nitric acid is
Difficult
View SolutionMeta-directing groups among the following are: $(a) -CN$,$(b) -COR$,$(c) -NHCOR$,$(d) -SO_3H$,$(e) -OCH_3$
Tropolone is
For preparing monoalkyl benzene,the acylation process is preferred over direct alkylation because:
Medium
View SolutionWhich of the following compounds will undergo electrophilic substitution more readily than benzene?
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo