Which of the following compounds reacts slowe | vedclass

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(A) Electrophilic aromatic substitution is facilitated by electron-donating groups (activating groups) and hindered by electron-withdrawing groups (de

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$C_6H_5NO_2$

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(A) Electrophilic aromatic substitution is facilitated by electron-donating groups (activating groups) and hindered by electron-withdrawing groups (deactivating groups).$C_6H_5NH_2$,$C_6H_5OH$,and $C_6H_5CH_3$ contain groups ($-NH_2$,$-OH$,$-CH_3$) that increase electron density in the benzene ring,making them more reactive than benzene.$C_6H_5NO_2$ contains a nitro group $(-NO_2)$,which is a strong electron-withdrawing group due to its $-I$ and $-M$ effects.This decreases the electron density of the benzene ring,making it less reactive towards electrophiles compared to benzene.Therefore,$C_6H_5NO_2$ reacts slower than benzene.

Which of the following compounds reacts slower than benzene in electrophilic bromination?

Similar Questions

The major product formed in the following reaction sequence is:
$C_6H_5-CHBr-CH_2Br$ $\xrightarrow[(ii) NaNH_2]{(i) alc. KOH}$ $\xrightarrow[(iii) \text{Red hot iron tube}, 873 K]{}$

What are the major products obtained in each case when compounds $P, Q,$ and $S$ are nitrated using a mixture of $HNO_3/H_2SO_4$?

For the given reaction:
$CH_{3}-CH=CHBr \xrightarrow[2. \text{Red hot iron tube}, 873 \text{ K}]{1. \text{NaNH}_{2}} A$ (major product)
Identify the major product $A$.

Which of the following structures are aromatic?

Hybridised states of carbon in graphite and diamond are respectively

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