The molecular formula of diphenylmethane is C | vedclass

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(A) Diphenylmethane has the structure $(C_6H_5)-CH_2-(C_6H_5)$.There are three distinct types of hydrogen atoms available for substitution:$1$. The tw

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$4$

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(A) Diphenylmethane has the structure $(C_6H_5)-CH_2-(C_6H_5)$.There are three distinct types of hydrogen atoms available for substitution:$1$. The two hydrogen atoms on the central $CH_2$ group (equivalent).$2$. The ortho,meta,and para positions on the two benzene rings.Due to the symmetry of the molecule,the substitution positions are:- Substitution at the central $CH_2$ carbon: $1$ isomer.- Substitution at the ortho position of either ring: $1$ isomer.- Substitution at the meta position of either ring: $1$ isomer.- Substitution at the para position of either ring: $1$ isomer.Wait,let us re-evaluate: The two rings are equivalent. The positions are: $CH_2$ $(1)$,ortho $(2)$,meta $(3)$,para $(4)$. Total structural isomers = $4$.

The molecular formula of diphenylmethane is $C_{13}H_{12}$. How many structural isomers are possible when one hydrogen atom is replaced by a chlorine atom?

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