The number of geometrical isomers for CH_3CH= | vedclass

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(C) The given compound is a polyene with $n = 3$ double bonds that can exhibit geometrical isomerism.For a polyene with $n$ double bonds where the end

Vedclass · Accepted Answer

$8$

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(C) The given compound is a polyene with $n = 3$ double bonds that can exhibit geometrical isomerism.For a polyene with $n$ double bonds where the ends are different,the number of geometrical isomers is given by the formula $2^n$.Here,the double bonds are at positions $2, 4,$ and $6$.Since the molecule is $CH_3-CH=CH-CH=CH-CH=CH-Cl$,the terminal groups are different ($-CH_3$ and $-Cl$).Therefore,the number of geometrical isomers $= 2^3 = 8$.

The number of geometrical isomers for $CH_3CH=CH-CH=CH-CH=CHCl$ is .............

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