How many cyclic isomers are possible for {C_5 | vedclass

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(D) The molecular formula ${C_5}{H_{10}}$ corresponds to a degree of unsaturation of $1$ $(5 - 10/2 + 1 = 1)$.For cyclic isomers,the possible structur

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$6$

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(D) The molecular formula ${C_5}{H_{10}}$ corresponds to a degree of unsaturation of $1$ $(5 - 10/2 + 1 = 1)$.For cyclic isomers,the possible structures are:$1$. Cyclopentane$2$. Methylcyclobutane$3$. $1,1$-Dimethylcyclopropane$4$. $1,2$-Dimethylcyclopropane (cis and trans isomers exist)$5$. EthylcyclopropaneCounting these,we have cyclopentane,methylcyclobutane,$1,1$-dimethylcyclopropane,$1,2$-dimethylcyclopropane (cis),$1,2$-dimethylcyclopropane (trans),and ethylcyclopropane.Total cyclic isomers = $6$.

How many cyclic isomers are possible for ${C_5}{H_{10}}$?

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