How many optical isomers are possible for the | vedclass

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(C) The given compound is $CH_3-CH(COOH)-CH(COOH)-CH_2CH_3$. It contains two chiral carbon atoms (marked with *): $CH_3-CH^*(COOH)-CH^*(COOH)-CH_2CH_3

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$4$

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(C) The given compound is $CH_3-CH(COOH)-CH(COOH)-CH_2CH_3$. It contains two chiral carbon atoms (marked with *): $CH_3-CH^*(COOH)-CH^*(COOH)-CH_2CH_3$. Since the two chiral carbons are attached to different groups (one is attached to $-CH_3$ and $-H$,the other to $-CH_2CH_3$ and $-H$),the molecule is asymmetric. The number of optical isomers is given by the formula $2^n$,where $n$ is the number of chiral centers. Here,$n = 2$,so the number of optical isomers = $2^2 = 4$.

How many optical isomers are possible for the compound $CH_3CH(COOH)-CH(COOH)CH_2CH_3$?

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