CCl_4 and CHCl_3 can be distinguished by .... | vedclass

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(A) $CHCl_3$ (chloroform) reacts with primary amines $(R-NH_2)$ in the presence of alcoholic $KOH$ to form isocyanides (carbylamines),which have a fou

Vedclass · Accepted Answer

$R-NH_2 + KOH$ (alc.)

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(A) $CHCl_3$ (chloroform) reacts with primary amines $(R-NH_2)$ in the presence of alcoholic $KOH$ to form isocyanides (carbylamines),which have a foul smell. This is known as the carbylamine test. $R-NH_2 + CHCl_3 + 3KOH (alc.) \rightarrow R-NC + 3KCl + 3H_2O$ $CCl_4$ does not give this reaction. Therefore,$CCl_4$ and $CHCl_3$ can be distinguished by using $R-NH_2 + KOH$ (alc.).

$CCl_4$ and $CHCl_3$ can be distinguished by .....

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