In the process of obtaining chlorine from bri | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The electrolysis of brine ($NaCl$ solution) involves the oxidation of chloride ions to chlorine gas at the anode: $2Cl^- (aq) \rightarrow Cl_2 (g)

Vedclass · Accepted Answer

$2.18$

Vedclass · Answer

(B) The electrolysis of brine ($NaCl$ solution) involves the oxidation of chloride ions to chlorine gas at the anode: $2Cl^- (aq) \rightarrow Cl_2 (g) + 2e^-$ $(E^\circ = -1.36 \ V)$.At the cathode,water is reduced: $2H_2O (l) + 2e^- \rightarrow H_2 (g) + 2OH^- (aq)$ $(E^\circ = -0.83 \ V)$.The overall cell reaction is $2Cl^- (aq) + 2H_2O (l) \rightarrow Cl_2 (g) + H_2 (g) + 2OH^- (aq)$.The standard cell potential is $E^\circ_{cell} = E^\circ_{cathode} - E^\circ_{anode} = -0.83 \ V - 1.36 \ V = -2.19 \ V$.Since the reaction is non-spontaneous,an external potential of at least $2.19 \ V$ (often approximated as $2.2 \ V$ or $2.18 \ V$ in textbooks) is required to drive the reaction.

In the process of obtaining chlorine from brine,the minimum value of $E_{cell}$ should be ....... $V$.

Similar Questions

What is a secondary cell? Give examples of it.

Standard electrode potentials for a few half cells are mentioned below:
$E^0_{Cu^{2+}/Cu} = 0.34 \ V, E^0_{Zn^{2+}/Zn} = -0.76 \ V$
$E^0_{Ag^{+}/Ag} = 0.80 \ V, E^0_{Mg^{2+}/Mg} = -2.37 \ V$
Which one of the following cells gives the most negative value of $\Delta G^0$?

What is the correct expression for $\Lambda_{m(NH_4OH)}^0$?

Calculate $\Delta_r G^o$ for the cell reaction:
$Zn_{(s)} + Cu^{2+}_{(aq)} \to Zn^{2+}_{(aq)} + Cu_{(s)}$
Given: $E^o_{Cu^{2+}/Cu} = 0.34 \, V, E^o_{Zn^{2+}/Zn} = -0.76 \, V$

What happens during the discharge of a lead storage battery?

Vedclass Test Series

Exam Paper Generator

Online Exam Module