pH of a solution of 10 mL 1 N sodium acetat | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The solution is a buffer containing a weak acid (acetic acid) and its salt (sodium acetate).Using the Henderson-Hasselbalch equation: $pH = pK_a +

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(A) The solution is a buffer containing a weak acid (acetic acid) and its salt (sodium acetate).Using the Henderson-Hasselbalch equation: $pH = pK_a + \log \frac{[Salt]}{[Acid]}$Number of milliequivalents of salt = $10 \ mL 	imes 1 \ N = 10 \ meq$.Number of milliequivalents of acid = $50 \ mL 	imes 2 \ N = 100 \ meq$.Total volume = $10 \ mL + 50 \ mL = 60 \ mL$.Since the volume cancels out in the ratio,we use milliequivalents: $\frac{[Salt]}{[Acid]} = \frac{10}{100} = 0.1$.$pK_a = -\log(1.8 	imes 10^{-5}) = 5 - \log(1.8) \approx 5 - 0.255 = 4.745$.$pH = 4.745 + \log(0.1) = 4.745 - 1 = 3.745$.The value is approximately $4$.

$pH$ of a solution of $10 \ mL$ $1 \ N$ sodium acetate and $50 \ mL$ $2 \ N$ acetic acid $(K_a = 1.8 \times 10^{-5})$ is approximately

Similar Questions

The $pK_a$ of a weak acid $(HA)$ is $4.5$. The $pOH$ of an aqueous buffered solution of $HA$ in which $50\%$ of the acid is neutralized in its titration with a strong base $(BOH)$ is

Which of the following mixtures will produce a buffer solution with $pH = 9$?

Buffer system helps to maintain blood $pH$ between .......

When $1.0 \ mL$ of dilute $HCl$ acid is added to $100 \ mL$ of a buffer solution with $pH = 4.0$,what will be the resulting $pH$ of the solution?

Which of the following is a buffer solution?

Vedclass Test Series

Exam Paper Generator

Online Exam Module