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(A) To determine the hybridization of carbon atoms,we analyze the bonding in each molecule:$1$. Acetonitrile $(CH_3CN)$: The carbon in the methyl grou

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Acetonitrile

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(A) To determine the hybridization of carbon atoms,we analyze the bonding in each molecule:$1$. Acetonitrile $(CH_3CN)$: The carbon in the methyl group is $sp^3$ hybridized,but the carbon in the nitrile group $(-CN)$ is $sp$ hybridized. Wait,the question asks where $sp^2$ carbon is $NOT$ present.$2$. Glycine $(NH_2-CH_2-COOH)$: The carbon in the carboxylic acid group $(-COOH)$ is $sp^2$ hybridized.$3$. Tartaric acid $(HOOC-CH(OH)-CH(OH)-COOH)$: The carbons in the two carboxylic acid groups are $sp^2$ hybridized.$4$. Formic acid $(HCOOH)$: The carbon in the carboxylic acid group is $sp^2$ hybridized.Re-evaluating the options: Acetonitrile contains $sp^3$ and $sp$ hybridized carbons. Glycine contains $sp^3$ and $sp^2$ hybridized carbons. Tartaric acid contains $sp^3$ and $sp^2$ hybridized carbons. Formic acid contains only an $sp^2$ hybridized carbon. Actually,in Acetonitrile $(CH_3-C \equiv N)$,the methyl carbon is $sp^3$ and the nitrile carbon is $sp$. Thus,$sp^2$ carbon is absent in Acetonitrile.

$sp^2$ carbon is not present in

Similar Questions

The ascending acidity order of the following $H$ atoms is:
$A: HC \equiv C-H$
$B: H_2C=CH-H$
$C: (CH_3)_3C-H$
$D: CH_3-CH_2-H$

Which of the following underlined carbon atoms possesses $sp$ hybridization?

$CH_3-CH_2-CH=CH_2$ has hybridisation

In the structure $CH_2 = CH - C \equiv CH$,what are the hybridization states of the carbon atoms that are connected to each other by a single bond?

Explain how the electronegativity of carbon atoms is related to their state of hybridization in an organic compound.

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