P_4O_{10} has short and long P-O bonds. The n | vedclass

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(D) The structure of $P_4O_{10}$ consists of a $P_4$ tetrahedron where each $P$ atom is bonded to three other $P$ atoms through oxygen bridges ($P-O-P

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$4$

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(D) The structure of $P_4O_{10}$ consists of a $P_4$ tetrahedron where each $P$ atom is bonded to three other $P$ atoms through oxygen bridges ($P-O-P$ bonds). Additionally,each $P$ atom is bonded to a terminal oxygen atom via a double bond $(P=O)$. These terminal $P=O$ bonds are shorter than the $P-O-P$ single bonds. In $P_4O_{10}$,there are $4$ such terminal $P=O$ bonds. Therefore,the number of short $P-O$ bonds is $4$.

$P_4O_{10}$ has short and long $P-O$ bonds. The number of short $P-O$ bonds in this compound is

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