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(B) Let the number of atoms of element $Y$ in the $ccp$ structure be $n = 4$.The number of tetrahedral voids $(T.V.)$ is $2n = 2 	imes 4 = 8$.Given t

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$X_4Y_3$

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(B) Let the number of atoms of element $Y$ in the $ccp$ structure be $n = 4$.The number of tetrahedral voids $(T.V.)$ is $2n = 2 	imes 4 = 8$.Given that element $X$ occupies $2/3$ of the tetrahedral voids,the number of $X$ atoms = $8 	imes \frac{2}{3} = \frac{16}{3}$.The ratio of $X:Y$ is $\frac{16}{3} : 4$,which simplifies to $16:12$ or $4:3$.Therefore,the molecular formula is $X_4Y_3$.

In a compound $XY$,the atoms of element $Y$ form a $ccp$ structure,while the atoms of element $X$ occupy $2/3$ of the tetrahedral voids. The molecular formula of the compound will be ..........

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