(B) According to Raoult's law for a solution containing a non-volatile solute,the relative lowering of vapor pressure is given by the equation: $\frac

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The relative lowering of vapor pressure is equal to the mole fraction of the solute.

(B) According to Raoult's law for a solution containing a non-volatile solute,the relative lowering of vapor pressure is given by the equation: $\frac{P_1^0 - P_1}{P_1^0} = x_2$. Here,$P_1^0$ is the vapor pressure of the pure solvent,$P_1$ is the vapor pressure of the solution,and $x_2$ is the mole fraction of the solute. Thus,the relative lowering of vapor pressure is equal to the mole fraction of the solute.

Class 12 Chemistry Solutions Lowering of vapour pressure

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According to Raoult's law for a non-volatile solute,which of the following is correct?

A
The decrease in vapor pressure is equal to the mole fraction of the solute.
B
The relative lowering of vapor pressure is equal to the mole fraction of the solute.
C
The vapor pressure of the solution is directly proportional to the mole fraction of the solvent.
D
The decrease in vapor pressure is directly proportional to the mole fraction of the solvent.

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Lowering of vapour pressure

The mass of non-volatile,non-electrolyte solute (molar mass $= 50 \ g \ mol^{-1}$) needed to be dissolved in $114 \ g$ octane to reduce its vapour pressure to $75\%$ is .............. $g$.

DifficultJEE MAIN 2018

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If the vapour pressure of a solution containing a non-volatile solute is $2\%$ less than the vapour pressure of pure water,find the molality of the solution.

Medium

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What will be the molar mass of a non-volatile solute if the vapour pressure of pure benzene is $450 \ mm \ Hg$ and it decreases to $400 \ mm \ Hg$ when $1.5 \ g$ of the solute is added to $30 \ g$ of benzene? (Atomic mass: $C=12, H=1$)

DifficultMHT CET 2020

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If $x \ g$ of a non-volatile,non-electrolytic solute is dissolved in $114 \ g$ of octane to reduce its vapour pressure to $80 \%$ of that of pure octane,then $x$ is ........... $g$. (Molar mass of solute $= 40 \ g/mol$)

Easy

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In an experiment,$1 \ g$ of a non-volatile solute was dissolved in $100 \ g$ of acetone (molar mass $= 58 \ g/mol$) at $298 \ K$. The vapour pressure of the solution was found to be $192.5 \ mm \ Hg$. The molecular weight of the solute is (vapour pressure of pure acetone $= 195 \ mm \ Hg$). (in $.24$)

MediumAIPMT 2001

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According to Raoult's law for a non-volatile solute,which of the following is correct?

Similar Questions

The mass of non-volatile,non-electrolyte solute (molar mass $= 50 \ g \ mol^{-1}$) needed to be dissolved in $114 \ g$ octane to reduce its vapour pressure to $75\%$ is .............. $g$.

If the vapour pressure of a solution containing a non-volatile solute is $2\%$ less than the vapour pressure of pure water,find the molality of the solution.

What will be the molar mass of a non-volatile solute if the vapour pressure of pure benzene is $450 \ mm \ Hg$ and it decreases to $400 \ mm \ Hg$ when $1.5 \ g$ of the solute is added to $30 \ g$ of benzene? (Atomic mass: $C=12, H=1$)

If $x \ g$ of a non-volatile,non-electrolytic solute is dissolved in $114 \ g$ of octane to reduce its vapour pressure to $80 \%$ of that of pure octane,then $x$ is ........... $g$. (Molar mass of solute $= 40 \ g/mol$)

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