The reaction N_2O_{4(g)} rightleftharpoons 2N | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction is $N_2O_{4(g)} \rightleftharpoons 2NO_{2(g)}$.Initial moles: $N_2O_4 = 0.8 \ mol$,$NO_2 = 0 \ mol$.At equilibrium,let the amount of

Vedclass · Accepted Answer

$0.06$

Vedclass · Answer

(A) The reaction is $N_2O_{4(g)} ightleftharpoons 2NO_{2(g)}$.Initial moles: $N_2O_4 = 0.8 \ mol$,$NO_2 = 0 \ mol$.At equilibrium,let the amount of $N_2O_4$ reacted be $x \ mol$.Then,$[N_2O_4] = (0.8 - x) \ M$ and $[NO_2] = 2x \ M$ (since volume is $1 \ L$).$K_c = \frac{[NO_2]^2}{[N_2O_4]} = \frac{(2x)^2}{0.8 - x} = 0.00466$.$4x^2 = 0.00466(0.8 - x) \implies 4x^2 + 0.00466x - 0.003728 = 0$.Using the quadratic formula $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$,we get $x \approx 0.03$.Therefore,$[NO_2] = 2x = 2 	imes 0.03 = 0.06 \ M$.

The reaction $N_2O_{4(g)} \rightleftharpoons 2NO_{2(g)}$ is started by taking $0.8 \ mol$ of $N_2O_4$ in a $1 \ L$ flask. If the equilibrium constant at $298 \ K$ is $0.00466 \ M$,the equilibrium concentration of $NO_2$ will be ........... $M$.

Similar Questions

For the reaction $N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g) + \text{heat}$,what is the relationship between $K_p$ and $K_c$?

$NH_4COONH_{2_{(s)}} \rightleftharpoons 2NH_{3_{(g)}} + CO_{2_{(g)}}$. If the equilibrium pressure is $3 \, atm$ for the above reaction,the $K_p$ for the reaction is:

The relationship between $K_{p}$ and $K_{c}$ is $K_{p}=K_{c}(RT)^{\Delta n_{g}}$. What would be the value of $\Delta n_{g}$ for the reaction $NH_{4}Cl_{(s)} \rightleftharpoons NH_{3(g)} + HCl_{(g)}$?

For the reaction $N_{2(g)} + 3H_{2(g)} \rightleftharpoons 2NH_{3(g)} + \text{heat}$,which of the following relations is correct?

For the reaction $2NOBr_{(g)} \rightleftharpoons 2NO_{(g)} + Br_{2(g)}$,if $P_{Br_2} = \frac{P}{9}$ at equilibrium and $P$ is the total pressure,find the value of $\frac{K_P}{P}$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module