For the elementary reaction A_{2(g)} + B_{2(g | vedclass

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(D) For an elementary reaction $A_{2(g)} + B_{2(g)} \rightleftharpoons 2AB_{(g)}$,the equilibrium constant $K_c$ is the ratio of the forward rate cons

Vedclass · Accepted Answer

$0.7 	imes 10^{3}$

Vedclass · Answer

(D) For an elementary reaction $A_{2(g)} + B_{2(g)} ightleftharpoons 2AB_{(g)}$,the equilibrium constant $K_c$ is the ratio of the forward rate constant $k_f$ to the reverse rate constant $k_r$.Given $r_f = k_f [A_2][B_2] = 1.7 	imes 10^{-18} [A_2][B_2]$,so $k_f = 1.7 	imes 10^{-18}$.Given $r_r = k_r [AB]^2 = 2.4 	imes 10^{-21} [AB]^2$,so $k_r = 2.4 	imes 10^{-21}$.$K_c = \frac{k_f}{k_r} = \frac{1.7 	imes 10^{-18}}{2.4 	imes 10^{-21}} = \frac{1.7}{2.4} 	imes 10^3 \approx 0.708 	imes 10^3 \approx 0.7 	imes 10^3$.

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