What will be the difference in heat at consta | vedclass

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(C) The combustion reaction for carbon monoxide is: $CO(g) + \frac{1}{2} O_2(g) \rightarrow CO_2(g)$.The change in the number of moles of gaseous prod

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$-300$

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(C) The combustion reaction for carbon monoxide is: $CO(g) + \frac{1}{2} O_2(g) ightarrow CO_2(g)$.The change in the number of moles of gaseous products and reactants is $\Delta n_g = n_p - n_r = 1 - (1 + 0.5) = -0.5 \, mol$.The relationship between heat at constant pressure $(q_p = \Delta H)$ and constant volume $(q_v = \Delta U)$ is given by $\Delta H = \Delta U + \Delta n_g RT$.Therefore,the difference is $\Delta H - \Delta U = \Delta n_g RT$.Given $T = 27 + 273 = 300 \, K$ and $R \approx 2 \, cal \, mol^{-1} K^{-1}$.Difference $= (-0.5) 	imes 2 	imes 300 = -300 \, cal$.

What will be the difference in heat at constant pressure and constant volume for the combustion of carbon monoxide at $27 \, ^oC$ in $cal$?

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