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(C) The work done by an ideal gas during expansion is given by the formula $w = -P \Delta V$.
Since $PV = nRT$,for a constant pressure process,$P \De

Vedclass · Accepted Answer

$-16.6$

Vedclass · Answer

(C) The work done by an ideal gas during expansion is given by the formula $w = -P \Delta V$.
Since $PV = nRT$,for a constant pressure process,$P \Delta V = nR \Delta T$.
Substituting the given values: $n = 1 \, 	ext{mol}$,$R = 8.3 \, 	ext{J K}^{-1} 	ext{mol}^{-1}$,and $\Delta T = 2 \, 	ext{K}$ (since a change of $2 \, ^\circ	ext{C}$ is equivalent to a change of $2 \, 	ext{K}$).
$w = -1 	imes 8.3 	imes 2 = -16.6 \, 	ext{J}$.
Thus,the work done is $-16.6 \, 	ext{J}$.

The work done when the temperature of $1 \, \text{mol}$ of an ideal gas is increased by $2 \, ^\circ\text{C}$ is ......... $J$.

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