The degree of hardness of water is generally | vedclass

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(C) The hardness of water is caused by the presence of dissolved calcium and magnesium salts. To express the total hardness of water,it is standard pr

Vedclass · Accepted Answer

$ppm$ by weight of $CaCO_3$ equivalent

Vedclass · Answer

(C) The hardness of water is caused by the presence of dissolved calcium and magnesium salts. To express the total hardness of water,it is standard practice to convert the concentration of all dissolved calcium and magnesium salts into an equivalent amount of $CaCO_3$. This is done because the molecular weight of $CaCO_3$ is $100 \ g/mol$,which simplifies calculations. Therefore,the degree of hardness is expressed as $ppm$ (parts per million) by weight of $CaCO_3$ equivalent.

List-$I$	List-$II$
$(a). H_2O + H_2S$	$(i). (H_3O^{+}, HS^{-})$
$(b). H_2O + N^{3-}$	$(ii). (NH_3, OH^{-})$
$(c). H_2O + SiCl_4$	$(iii). (OH^{-}, H_3S^{+})$
$(d). H_2O + F_2$	$(iv). (SiO_2, HCl)$
	$(v). (SiO_4^{4-}, Cl_2)$
	$(vi). (O_2, F^{-})$
	$(vii). (HF, OH^{-})$
	$(viii). (OH^{-}, NH_3)$

The degree of hardness of water is generally expressed in terms of which of the following?

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