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(A) The production of dihydrogen gas $(H_2)$ by the reaction of metals with acids or other reagents depends on the position of the metal in the electr

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$Cu + 	ext{dil. } HCl$

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(A) The production of dihydrogen gas $(H_2)$ by the reaction of metals with acids or other reagents depends on the position of the metal in the electrochemical series.Metals that are more reactive than hydrogen (i.e.,have a negative standard reduction potential) can displace hydrogen from acids.$Cu$ (Copper) is below hydrogen in the electrochemical series,meaning it has a positive standard reduction potential.Therefore,$Cu$ cannot displace hydrogen from dilute $HCl$ or other non-oxidizing acids.In contrast,$Fe$ reacts with $H_2SO_4$ to produce $FeSO_4$ and $H_2$,$Mg$ reacts with steam to produce $MgO$ and $H_2$,and $Na$ reacts with alcohol to produce sodium alkoxide and $H_2$.

Which of the following pairs will not produce dihydrogen gas?

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