(A) The relationship between normality $(N)$ and volume strength $(V)$ of $H_2O_2$ is given by the formula: $V = 5.6 \times N$. Given,$N = 3.0 \ N$. S

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(A) The relationship between normality $(N)$ and volume strength $(V)$ of $H_2O_2$ is given by the formula: $V = 5.6 \times N$. Given,$N = 3.0 \ N$. Substituting the value: $V = 5.6 \times 3.0 = 16.8$. Thus,the volume strength of the $3.0 \ N$ $H_2O_2$ solution is $16.8 \ \text{volumes}$.