Under normal conditions,the hydrogen molecule is not reactive because .........
- AHydrogen has many isotopes
- BThe corresponding $\Delta S^o$ value is very low
- CThe bond dissociation energy of the hydrogen molecule is very high
- DThe activation energy of the hydrogen molecule is very low
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$H_2C_2O_4 \xrightarrow{\Delta} \text{gas } (A) + \text{gas } (B) + \text{liquid } (C)$.
Gas $(A)$ burns with a blue flame and is oxidised to gas $(B)$.
Gas $(A) + Cl_2 \to (D)$.
$A, B$ and $D$ are:
Gas $(A)$ burns with a blue flame and is oxidised to gas $(B)$.
Gas $(A) + Cl_2 \to (D)$.
$A, B$ and $D$ are:
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View SolutionMatch the following:
List-$I$ List-$II$ $A$. Electron-deficient hydride $I$. $CH_4$ $B$. Electron-precise hydride $II$. $B_2H_6$ $C$. Electron-rich hydride $III$. $CaH_2$ $D$. Saline hydride $IV$. $NiH_{0.6}$ $V$. $PH_3$
| List-$I$ | List-$II$ |
| $A$. Electron-deficient hydride | $I$. $CH_4$ |
| $B$. Electron-precise hydride | $II$. $B_2H_6$ |
| $C$. Electron-rich hydride | $III$. $CaH_2$ |
| $D$. Saline hydride | $IV$. $NiH_{0.6}$ |
| $V$. $PH_3$ |
An alkali metal hydride $(NaH)$ reacts with diborane in '$A$' to give a tetrahedral compound '$B$' which is extensively used as a reducing agent in organic synthesis. The compounds '$A$' and '$B$' respectively are
MediumKCET 2015
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