What product is formed when I_2 reacts with H | vedclass

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(C) In a basic medium,$H_2O_2$ acts as a strong reducing agent. The reaction between iodine $(I_2)$ and hydrogen peroxide $(H_2O_2)$ in the presence o

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$IO_3^-$

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(C) In a basic medium,$H_2O_2$ acts as a strong reducing agent. The reaction between iodine $(I_2)$ and hydrogen peroxide $(H_2O_2)$ in the presence of a base $(OH^-)$ is: $I_2 + H_2O_2 + 2OH^- \rightarrow 2I^- + 2H_2O + O_2$. However,if $I_2$ is in excess or under specific conditions,it can be oxidized to iodate $(IO_3^-)$. In the context of standard redox reactions involving $H_2O_2$ as an oxidizing agent in basic medium,$I_2$ is oxidized to $IO_3^-$. The balanced equation is: $I_2 + 5H_2O_2 + 2OH^- \rightarrow 2IO_3^- + 6H_2O$.

What product is formed when $I_2$ reacts with $H_2O_2$ in a basic medium?

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