Which of the following compounds is the most | vedclass

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(A) Volatility is inversely proportional to the boiling point of a substance.For the hydrides of group $14$ elements $(CH_4, SiH_4, GeH_4, SnH_4)$,the

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$CH_4$

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(A) Volatility is inversely proportional to the boiling point of a substance.For the hydrides of group $14$ elements $(CH_4, SiH_4, GeH_4, SnH_4)$,the molecular mass increases as we move down the group from $C$ to $Sn$.As the molecular mass increases,the magnitude of van der Waals forces of attraction increases,leading to an increase in the boiling point.Therefore,the boiling point order is $CH_4 Since $CH_4$ has the lowest boiling point,it is the most volatile compound among the given options.

List-$I$	List-$II$
$A$. Coke	$I$. Carbon atoms are $sp^3$ hybridised
$B$. Diamond	$II$. Used as a dry lubricant
$C$. Fullerene	$III$. Used as a reducing agent
$D$. Graphite	$IV$. Cage like molecules

Which of the following compounds is the most volatile among $CH_4, SiH_4, GeH_4, SnH_4$?

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$(BN)_n$ exists in

Match List-$I$ with List-$II$.

List-$I$ List-$II$

$A$. Coke $I$. Carbon atoms are $sp^3$ hybridised

$B$. Diamond $II$. Used as a dry lubricant

$C$. Fullerene $III$. Used as a reducing agent

$D$. Graphite $IV$. Cage like molecules

Choose the correct answer from the options given below:

$SiCl_4$ on hydrolysis forms '$X$' and $HCl$. Compound '$X$' loses water at $1000^{\circ} C$ and gives '$Y$'. Compounds '$X$' and '$Y$' respectively are:

$C_{60}$,an allotrope of carbon,contains:

What do you understand by $(a)$ inert pair effect,$(b)$ allotropy,and $(c)$ catenation?

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