Phosphine is prepared by the reaction between $............$.
- A$P$ and $H_2SO_4$
- B$P$ and $NaOH$
- C$P$ and $H_2S$
- D$P$ and $HNO_3$
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Similar Questions
Strong reducing behaviour of $H_3PO_2$ is due to
MediumNEET 2017
View SolutionThe correct code for stability of oxidation states for given cations is:
$(i)$ $Pb^{2+} > Pb^{4+}, Tl^{+} < Tl^{3+}$
$(ii)$ $Bi^{3+} < Sb^{3+}, Sn^{2+} < Sn^{4+}$
$(iii)$ $Pb^{2+} > Pb^{4+}, Bi^{3+} > Bi^{5+}$
$(iv)$ $Tl^{3+} < In^{3+}, Sn^{2+} > Sn^{4+}$
$(v)$ $Sn^{2+} < Pb^{2+}, Sn^{4+} > Pb^{4+}$
$(vi)$ $Sn^{2+} < Pb^{2+}, Sn^{4+} < Pb^{4+}$
$(i)$ $Pb^{2+} > Pb^{4+}, Tl^{+} < Tl^{3+}$
$(ii)$ $Bi^{3+} < Sb^{3+}, Sn^{2+} < Sn^{4+}$
$(iii)$ $Pb^{2+} > Pb^{4+}, Bi^{3+} > Bi^{5+}$
$(iv)$ $Tl^{3+} < In^{3+}, Sn^{2+} > Sn^{4+}$
$(v)$ $Sn^{2+} < Pb^{2+}, Sn^{4+} > Pb^{4+}$
$(vi)$ $Sn^{2+} < Pb^{2+}, Sn^{4+} < Pb^{4+}$
Which of the following does not give oxygen on heating?
Medium
View SolutionIn group $-15$,as we move from $N$ to $Bi$,the $M_2O_3$ type oxides become ...... .
Easy
View SolutionWhen concentrated $H_2SO_4$ is added to dry $KNO_3$,brown fumes evolve. These fumes are
MediumIIT 1987
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