Which of the following bonds is the most pola | vedclass

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(C) The polarity of a bond is determined by the difference in electronegativity between the two bonded atoms. The greater the difference,the more pola

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$N - F$

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(C) The polarity of a bond is determined by the difference in electronegativity between the two bonded atoms. The greater the difference,the more polar the bond.Electronegativity values (Pauling scale): $N = 3.04$,$Cl = 3.16$,$O = 3.44$,$F = 3.98$.Differences in electronegativity:$N - Cl$: $|3.04 - 3.16| = 0.12$$O - F$: $|3.44 - 3.98| = 0.54$$N - F$: $|3.04 - 3.98| = 0.94$$N - N$: $|3.04 - 3.04| = 0.00$Comparing these values,the $N - F$ bond has the largest difference in electronegativity,making it the most polar bond.

Which of the following bonds is the most polar?

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