The hybridization states of the chlorine atom | vedclass

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(A) The hybridization of the central atom can be calculated using the formula: $H = \frac{1}{2} [V + M - C + A]$,where $V$ is the number of valence el

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$sp^3, sp^3, sp^3$

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(A) The hybridization of the central atom can be calculated using the formula: $H = \frac{1}{2} [V + M - C + A]$,where $V$ is the number of valence electrons,$M$ is the number of monovalent atoms,$C$ is the cationic charge,and $A$ is the anionic charge.For $ClO_4^-$: $H = \frac{1}{2} [7 + 0 - 0 + 1] = 4$,which corresponds to $sp^3$ hybridization.For $ClO_3^-$: $H = \frac{1}{2} [7 + 0 - 0 + 1] = 4$,which corresponds to $sp^3$ hybridization.For $ClO_2^-$: $H = \frac{1}{2} [7 + 0 - 0 + 1] = 4$,which corresponds to $sp^3$ hybridization.In all three ions,the chlorine atom is $sp^3$ hybridized due to the presence of lone pairs and bonding pairs.

The hybridization states of the chlorine atom in $ClO_4^-$,$ClO_3^-$,and $ClO_2^-$ are respectively .....

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