Which of the following molecules is planar?

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(B) To determine the geometry of the given $Xe$ compounds,we look at their hybridization and lone pairs:$1$. $XeO_4$: $sp^3$ hybridization,tetrahedral

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$XeF_4$

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(B) To determine the geometry of the given $Xe$ compounds,we look at their hybridization and lone pairs:$1$. $XeO_4$: $sp^3$ hybridization,tetrahedral geometry (non-planar).$2$. $XeF_4$: $sp^3d^2$ hybridization with $2$ lone pairs,square planar geometry (planar).$3$. $XeOF_4$: $sp^3d^2$ hybridization with $1$ lone pair,square pyramidal geometry (non-planar).$4$. $XeO_3$: $sp^3$ hybridization with $1$ lone pair,pyramidal geometry (non-planar).Therefore,$XeF_4$ is the only planar molecule.

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