$A$ metal $M$ reacts with $N_2$ to form a compound $A$ $(M_3N)$. Heating $A$ at a high temperature gives back $M$,and passing $A$ through $H_2O$ results in the evolution of gas $B$. Gas $B$ turns $CuSO_4$ solution blue. What are $A$ and $B$ respectively?

  • A
    $Mg_3N_2$ and $NH_3$
  • B
    $Na_3N$ and $NH_3$
  • C
    $Li_3N$ and $NH_3$
  • D
    $AlN$ and $NH_3$

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