When a solution of AgNO_3 is added to a solut | vedclass

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(B) The reaction between $AgNO_3$ and $KI$ is: $AgNO_3 + KI \rightarrow AgI(s) + KNO_3$. For a negatively charged $AgI$ sol,the dispersion medium must

Vedclass · Accepted Answer

$50 \ mL$ of $0.1 \ M \ AgNO_3 + 50 \ mL$ of $0.2 \ M \ KI$

Vedclass · Answer

(B) The reaction between $AgNO_3$ and $KI$ is: $AgNO_3 + KI \rightarrow AgI(s) + KNO_3$. For a negatively charged $AgI$ sol,the dispersion medium must contain an excess of $I^-$ ions,which get adsorbed on the surface of $AgI$ particles. This occurs when $KI$ is in excess. In option $B$,$50 \ mL$ of $0.2 \ M \ KI$ provides $10 \ mmol$ of $KI$,while $50 \ mL$ of $0.1 \ M \ AgNO_3$ provides $5 \ mmol$ of $AgNO_3$. Since $KI$ is in excess,$I^-$ ions are adsorbed on $AgI$ to form a negatively charged sol.

Expt. No.	Weight of $X$ (in $mg$) added to gold sol	Coagulation
$1$	$24$	Not prevented
$2$	$23$	Not prevented
$3$	$26$	prevented
$4$	$27$	prevented
$5$	$25$	prevented

When a solution of $AgNO_3$ is added to a solution of $KI$,a negatively charged sol is formed when they are in which of the following proportions?

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