23 g of Na metal reacts with ethanol to prod | vedclass

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(C) The chemical reaction between sodium $(Na)$ and ethanol $(C_2H_5OH)$ is: $2C_2H_5OH + 2Na \rightarrow 2C_2H_5ONa + H_2$ From the stoichiometry of

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$1/2$ mole of $H_2$

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(C) The chemical reaction between sodium $(Na)$ and ethanol $(C_2H_5OH)$ is: $2C_2H_5OH + 2Na ightarrow 2C_2H_5ONa + H_2$ From the stoichiometry of the reaction,$2 	ext{ moles}$ of $Na$ produce $1 	ext{ mole}$ of $H_2$. Given mass of $Na = 23 \ g$. Molar mass of $Na = 23 \ g/mol$. Number of moles of $Na = \frac{23 \ g}{23 \ g/mol} = 1 	ext{ mole}$. Since $2 	ext{ moles}$ of $Na$ produce $1 	ext{ mole}$ of $H_2$,then $1 	ext{ mole}$ of $Na$ will produce $\frac{1}{2} 	ext{ mole}$ of $H_2$.

$23 \ g$ of $Na$ metal reacts with ethanol to produce which of the following?

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