An organic compound with the molecular formul | vedclass

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(B) $1$. The molecular formula $C_3H_6O$ corresponds to a degree of unsaturation of $1$ $(3 - 6/2 + 1 = 1)$.$2$. The compound does not react with $2,4

Vedclass · Accepted Answer

$CH_2=CH-OCH_3$

Vedclass · Answer

(B) $1$. The molecular formula $C_3H_6O$ corresponds to a degree of unsaturation of $1$ $(3 - 6/2 + 1 = 1)$.$2$. The compound does not react with $2,4-DNP$,which indicates the absence of a carbonyl group (aldehyde or ketone).$3$. The compound does not react with sodium metal,which indicates the absence of an active hydrogen atom (like in alcohols or phenols).$4$. Given these conditions,the compound must be an ether with a double bond (unsaturated ether).$5$. Among the options,$CH_2=CH-OCH_3$ (methoxyethene) fits the molecular formula $C_3H_6O$,lacks a carbonyl group,and lacks an active hydrogen atom.

An organic compound with the molecular formula $C_3H_6O$ does not give a precipitate with $2,4-$dinitrophenylhydrazine $(2,4-DNP)$ and does not react with sodium metal. What is this compound?

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