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(B) The chemical reaction is: $BaO_2 + H_2SO_4 \longrightarrow BaSO_4 + H_2O_2$. In the products $BaSO_4$ and $H_2O_2$,the most electronegative elemen

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$-1$ and $-2$

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(B) The chemical reaction is: $BaO_2 + H_2SO_4 \longrightarrow BaSO_4 + H_2O_2$. In the products $BaSO_4$ and $H_2O_2$,the most electronegative element is oxygen $(O)$. In $BaSO_4$,the oxidation state of oxygen is $-2$. In $H_2O_2$ (hydrogen peroxide),the oxidation state of oxygen is $-1$. Thus,the oxidation states of the most electronegative element (oxygen) in the products are $-2$ and $-1$.

In the reaction between $BaO_2$ and $H_2SO_4$,the oxidation state of the most electronegative element in the products is .......

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