In the reaction CH_3CH_2OH xrightarrow{OH^-} | vedclass

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(B) In the reactant $CH_3-CH_2OH$,the oxidation state of the $C$ atom in the $CH_3$ group is $-3$,and the oxidation state of the $C$ atom in the $CH_2

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$C$ of $CH_2$

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(B) In the reactant $CH_3-CH_2OH$,the oxidation state of the $C$ atom in the $CH_3$ group is $-3$,and the oxidation state of the $C$ atom in the $CH_2$ group is $-1$.In the product $CH_3-CHO$,the oxidation state of the $C$ atom in the $CH_3$ group remains $-3$,while the oxidation state of the $C$ atom in the $CHO$ group becomes $+1$.Since the oxidation state of the $C$ atom in the $CH_2$ group increases from $-1$ to $+1$,it undergoes oxidation.

In the reaction $CH_3CH_2OH \xrightarrow{OH^-} CH_3CHO$,which carbon atom undergoes oxidation?

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