In the reaction between KI and acidic potassi | vedclass

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Question

(D) The reaction between potassium dichromate $(K_2Cr_2O_7)$ and potassium iodide $(KI)$ in an acidic medium is given by the following equation:$Cr_2O

Vedclass · Accepted Answer

$+3$

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(D) The reaction between potassium dichromate $(K_2Cr_2O_7)$ and potassium iodide $(KI)$ in an acidic medium is given by the following equation:$Cr_2O_7^{2-} + 14H^+ + 6I^- \rightarrow 2Cr^{3+} + 7H_2O + 3I_2$In this reaction,the dichromate ion $(Cr_2O_7^{2-})$ acts as an oxidizing agent and is reduced to the chromium$(III)$ ion $(Cr^{3+})$.Therefore,the oxidation state of chromium changes from $+6$ in $K_2Cr_2O_7$ to $+3$ in the final product $Cr^{3+}$.

In the reaction between $KI$ and acidic potassium dichromate solution,the oxidation state of chromium in the final product is ........

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