$1 \ mol$ of compound $N_2H_4$ loses $10 \ mol$ of electrons to form a new compound $Y$. Assuming all nitrogen atoms are present in compound $Y$,what is the oxidation state of $N$ in compound $Y$?
- A$-1$
- B$-3$
- C$+3$
- D$+5$
Explore More
Similar Questions
Arrange the following molecules in the increasing order of the oxidation number of $S$: $SO_3^{2-}$,$S_2O_4^{2-}$,and $S_2O_6^{2-}$.
Medium
View SolutionWhat is the change in oxidation number of $S$ in the following reaction?
$H_2S + NO_3^- \longrightarrow H_2O + NO + S$
$H_2S + NO_3^- \longrightarrow H_2O + NO + S$
Which of the following is $NOT$ correct for $C_3O_2$?
Medium
View SolutionThe equivalent weight of potassium permanganate in an alkaline medium is........
Medium
View SolutionIn which of the following compounds is chlorine in the $+1$ oxidation state?
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo