Assertion: Two bodies of masses M and m (M | vedclass

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(D) The forces acting on a body of mass $m$ are its weight $mg$ acting vertically downward and air resistance $F$ acting vertically upward.The net for

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If both the $Assertion$ and $Reason$ are incorrect.

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(D) The forces acting on a body of mass $m$ are its weight $mg$ acting vertically downward and air resistance $F$ acting vertically upward.The net force is $F_{net} = mg - F$.The acceleration of the body is $a = \frac{F_{net}}{m} = g - \frac{F}{m}$.For the body of mass $M$,the acceleration is $a_M = g - \frac{F}{M}$.For the body of mass $m$,the acceleration is $a_m = g - \frac{F}{m}$.Since $M > m$,it follows that $\frac{F}{M}  a_m$.The body with the larger mass $M$ will have a greater acceleration and will reach the ground first.Therefore,the $Assertion$ is incorrect because they do not reach simultaneously,and the $Reason$ is also incorrect because the accelerations are not the same.

Column-$I$	Column-$II$
$(1)$ Static friction	$(a)$ Limiting friction
$(2)$ Rolling friction	$(b)$ Ball bearing
	$(c)$ Object moving on a road

$Assertion$: Two bodies of masses $M$ and $m$ $(M > m)$ are allowed to fall from the same height. If the air resistance for each is the same,then both bodies will reach the Earth simultaneously.
$Reason$: For the same air resistance,the acceleration of both bodies will be the same.

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Column-$I$ Column-$II$

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$Assertion$: Two bodies of masses $M$ and $m$ $(M > m)$ are allowed to fall from the same height. If the air resistance for each is the same,then both bodies will reach the Earth simultaneously.$Reason$: For the same air resistance,the acceleration of both bodies will be the same.