(D) The potential energy $U$ of a spring is given by the formula $U = \frac{1}{2} K x^2$,where $K$ is the spring constant and $x$ is the extension or

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If the $Assertion$ is incorrect but $Reason$ is correct.

(D) The potential energy $U$ of a spring is given by the formula $U = \frac{1}{2} K x^2$,where $K$ is the spring constant and $x$ is the extension or compression.This equation shows that $U \propto x^2$.The graph of $U$ versus $x$ represents a parabola,not a straight line.Therefore,the $Assertion$ is incorrect because the relationship is quadratic,not linear.The $Reason$ is correct because it correctly states that the potential energy is proportional to the square of the extension or compression $(U \propto x^2)$.

Class 11 Physics Work, Energy, Power and Collision Work Done by Spring and Potential Energy of Spring

Easy

$Assertion$ : Graph between potential energy of a spring versus the extension or compression of the spring is a straight line.
$Reason$ : Potential energy of a stretched or compressed spring is proportional to the square of extension or compression.

AIIMS 2017 All AIIMS

A
If both $Assertion$ and $Reason$ are correct and the $Reason$ is a correct explanation of the $Assertion$.
B
If both $Assertion$ and $Reason$ are correct but $Reason$ is not a correct explanation of the $Assertion$.
C
If both the $Assertion$ and $Reason$ are incorrect.
D
If the $Assertion$ is incorrect but $Reason$ is correct.

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Class 11

Physics Questions

Chapter

Work, Energy, Power and Collision

Subtopic

Work Done by Spring and Potential Energy of Spring

Previous Year

AIIMS 2017 Paper All AIIMS years →

$K$ is the force constant of a spring. The work done in increasing its extension from $l_1$ to $l_2$ will be

Medium

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$A$ block of mass $m$ moving with a velocity $v_0$ on a smooth horizontal surface strikes and compresses a spring of stiffness $k$ until the mass comes to rest,as shown in the figure. This phenomenon is observed by two observers:
$A$: standing on the horizontal surface
$B$: standing on the block
To an observer $A$,the work done by the spring force is

Medium

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$A$ spring $40 \, mm$ long is stretched by the application of a force. If $10 \, N$ force is required to stretch the spring by $1 \, mm$,then the work done in stretching the spring by $40 \, mm$ is ............. $J$.

MediumAIIMS 1998

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The work done in joules in increasing the extension of a spring of stiffness $10\, N/cm$ from $4\, cm$ to $6\, cm$ is:

Medium

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$A$ mass of $1 \ kg$ falls from a height of $1 \ m$ and lands on a massless platform supported by a spring having spring constant $15 \ N \ m^{-1}$ as shown in the figure. The maximum compression of the spring is. (acceleration due to gravity $= 10 \ m \ s^{-2}$)

DifficultAP EAMCET 2022

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$Assertion$ : Graph between potential energy of a spring versus the extension or compression of the spring is a straight line.$Reason$ : Potential energy of a stretched or compressed spring is proportional to the square of extension or compression.

Similar Questions

$K$ is the force constant of a spring. The work done in increasing its extension from $l_1$ to $l_2$ will be

$A$ spring $40 \, mm$ long is stretched by the application of a force. If $10 \, N$ force is required to stretch the spring by $1 \, mm$,then the work done in stretching the spring by $40 \, mm$ is ............. $J$.

The work done in joules in increasing the extension of a spring of stiffness $10\, N/cm$ from $4\, cm$ to $6\, cm$ is:

$A$ mass of $1 \ kg$ falls from a height of $1 \ m$ and lands on a massless platform supported by a spring having spring constant $15 \ N \ m^{-1}$ as shown in the figure. The maximum compression of the spring is. (acceleration due to gravity $= 10 \ m \ s^{-2}$)

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$Assertion$ : Graph between potential energy of a spring versus the extension or compression of the spring is a straight line.
$Reason$ : Potential energy of a stretched or compressed spring is proportional to the square of extension or compression.