1, m^3 of water is brought inside a lake up t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The formula for bulk modulus $K$ is given by $K = \frac{P}{\Delta V/V}$, where $P$ is the change in pressure, $V$ is the initial volume, and $\Del

Vedclass · Accepted Answer

$9.1	imes10^{-4}\, m^3$

Vedclass · Answer

(C) The formula for bulk modulus $K$ is given by $K = \frac{P}{\Delta V/V}$, where $P$ is the change in pressure, $V$ is the initial volume, and $\Delta V$ is the change in volume.Rearranging for $\Delta V$, we get $\Delta V = \frac{PV}{K}$.The pressure at depth $h$ is $P = hho g = 200 	imes 10^3 	imes 10 = 2 	imes 10^6\, N/m^2$.The bulk modulus is $K = 22000\, 	ext{atm} = 22000 	imes 10^5 = 2.2 	imes 10^9\, N/m^2$.Given $V = 1\, m^3$, substituting the values:$\Delta V = \frac{2 	imes 10^6 	imes 1}{2.2 	imes 10^9} = \frac{2}{2200} = \frac{1}{1100} \approx 9.09 	imes 10^{-4}\, m^3$.Rounding to the nearest option, $\Delta V \approx 9.1 	imes 10^{-4}\, m^3$.

Similar Questions

The isothermal bulk modulus of a perfect gas at normal pressure is

$A$ rubber ball is taken to a $100\, m$ deep lake and its volume changes by $0.1\%$. The bulk modulus of rubber is nearly

The fractional change in the volume of a glass slab when subjected to a hydraulic pressure of $14 \,atm$ is (Bulk modulus of glass $= 40 \times 10^9 \,N/m^2$).

The Bulk Modulus for an incompressible liquid is

The density $\rho$ of water of bulk modulus $B$ at a depth $y$ in the ocean is related to the density at the surface $\rho_0$ by the relation:

Vedclass Test Series

Exam Paper Generator

Online Exam Module