Assertion : In an isothermal process,the whol | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The first law of thermodynamics is given by $\Delta Q = \Delta U + P\Delta V$.For an ideal gas,the internal energy $U$ is a function of temperatur

Vedclass · Accepted Answer

If both the Assertion and Reason are incorrect.

Vedclass · Answer

(D) The first law of thermodynamics is given by $\Delta Q = \Delta U + P\Delta V$.For an ideal gas,the internal energy $U$ is a function of temperature $T$ only $(U = f(T))$.In an isothermal process,the temperature remains constant,so $\Delta T = 0$.Since $\Delta U = nC_v\Delta T$,it follows that $\Delta U = 0$ for an isothermal process.Substituting this into the first law: $\Delta Q = 0 + P\Delta V$,which means $\Delta Q = P\Delta V$.Therefore,the heat supplied is converted into work done by the system,not internal energy.Thus,the Assertion is incorrect,and the Reason is a correct statement of the first law of thermodynamics.

$Assertion :$ In an isothermal process,the whole of the heat supplied to the body is converted into internal energy.
$Reason :$ According to the first law of thermodynamics,$\Delta Q = \Delta U + P\Delta V$.

Similar Questions

When heat is given to a gas in an isothermal process,then there will be

The condition $dQ = dW$ holds good in which of the following?

Select the $WRONG$ statement from the following. For an isothermal process:

An ideal gas is subjected to an isothermal expansion such that its volume changes from $V_i$ to $V_f$ and pressure from $P_i$ to $P_f$. The work done on the gas is:

One mole of an ideal gas expands at a constant temperature of $300 \, K$ from an initial volume of $10 \, L$ to a final volume of $20 \, L$. The work done in expanding the gas is ...... $J$. $(R = 8.31 \, J/mol \cdot K)$

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$Assertion :$ In an isothermal process,the whole of the heat supplied to the body is converted into internal energy.$Reason :$ According to the first law of thermodynamics,$\Delta Q = \Delta U + P\Delta V$.