Assertion : In free expansion of an ideal gas | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Free expansion of an ideal gas is an adiabatic process $(Q = 0)$ where no work is done $(W = 0)$. Since $\Delta U = Q - W$,the internal energy rem

Vedclass · Accepted Answer

If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.

Vedclass · Answer

(A) Free expansion of an ideal gas is an adiabatic process $(Q = 0)$ where no work is done $(W = 0)$. Since $\Delta U = Q - W$,the internal energy remains constant,meaning the temperature of the ideal gas does not change. However,the gas occupies a larger volume,which increases the number of available microstates. The change in entropy for an ideal gas is given by $\Delta S = nR \ln(V_f/V_i)$. Since $V_f > V_i$,$\Delta S > 0$,so entropy increases. Furthermore,all natural (irreversible) processes are accompanied by an increase in the total entropy of the universe. Thus,both the Assertion and the Reason are correct,and the Reason correctly explains the Assertion.

$Assertion :$ In free expansion of an ideal gas,the entropy increases.
$Reason :$ Entropy increases in all natural processes.

Similar Questions

When a gas in a vacuum chamber expands suddenly,which of the following is true?

What is an irreversible process and what is a reversible process?

What is a quasi-static process?

$A$ balloon filled with helium ($32^{\circ} C$ and $1.7 \; atm$) bursts. Immediately afterwards,the expansion of helium can be considered as:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$Assertion :$ In free expansion of an ideal gas,the entropy increases.$Reason :$ Entropy increases in all natural processes.