$H_2S$ acts only as a reducing agent while $SO_2$ can act both as a reducing and oxidizing agent because

  • A
    $S$ in $H_2S$ has $-2$ oxidation state
  • B
    $S$ in $SO_2$ has oxidation state $+4$
  • C
    Hydrogen in $H_2S$ is more electropositive than oxygen
  • D
    Both $(a)$ and $(b)$

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