A block P of mass m is placed on a frictionle | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) When two blocks perform simple harmonic motion together,the system acts as a single body of mass $2m$ attached to a spring of constant $k$.The acc

Vedclass · Accepted Answer

$\frac{kA}{2}$

Vedclass · Answer

(B) When two blocks perform simple harmonic motion together,the system acts as a single body of mass $2m$ attached to a spring of constant $k$.The acceleration of the system at any displacement $x$ is given by $a = -\omega^2 x$,where $\omega^2 = \frac{k}{2m}$.At the extreme position,the displacement is $x = A$,so the magnitude of acceleration is $a_{max} = \omega^2 A = \frac{k}{2m} A = \frac{kA}{2m}$.The friction force $f$ acting on block $P$ provides the necessary acceleration to it. Since block $P$ has mass $m$,the friction force is $f = m \cdot a$.At the extreme position,the friction force reaches its maximum value: $f_{max} = m \cdot a_{max} = m \left( \frac{kA}{2m} \right) = \frac{kA}{2}$.

Similar Questions

$A$ block of mass $m$ is attached to two springs of spring constants $k_1$ and $k_2$ as shown in the figure. The block is displaced by $x$ towards the right and released. The velocity of the block when it is at $x/2$ will be

The time period of oscillation for the given combination will be:

An object is attached to the bottom of a light vertical spring and set vibrating. The maximum speed of the object is $15 \,cm/s$ and the period is $628 \,ms$. The amplitude of the motion in $cm$ is:

$A$ mass suspended from a vertical spring performs $S.H.M.$ with a period of $T = 0.1 \ s$. The spring is unstretched at the highest point of its motion. What is the maximum speed of the mass? (Take gravitational acceleration $g = 10 \ m/s^2$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module