Al^{3+} has a lower ionic radius than Mg^{2+} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $Al^{3+}$ and $Mg^{2+}$ have an equal number of electrons ($10$ electrons) and are,therefore,isoelectronic.For isoelectronic species,the ionic rad

Vedclass · Accepted Answer

$Al^{3+}$ has a higher nuclear charge than $Mg^{2+}$

Vedclass · Answer

(B) $Al^{3+}$ and $Mg^{2+}$ have an equal number of electrons ($10$ electrons) and are,therefore,isoelectronic.For isoelectronic species,the ionic radius depends upon the effective nuclear charge $(Z_{eff})$.Ionic radius is inversely proportional to the effective nuclear charge.Since $Al$ $(Z=13)$ has a higher atomic number than $Mg$ $(Z=12)$,$Al^{3+}$ experiences a greater effective nuclear charge than $Mg^{2+}$.Consequently,the electrons in $Al^{3+}$ are pulled more strongly towards the nucleus,resulting in a smaller ionic radius.

$Al^{3+}$ has a lower ionic radius than $Mg^{2+}$ because

Similar Questions

The correct order of covalent radii of $Si$,$Ge$,and $Sn$ is:

The correct sequence which shows the decreasing order of the ionic radii of the elements is:

Among the elements $Li$,$N$,$C$ and $Be$,the one with the largest atomic radius is

Arrange the following elements in the increasing order of their atomic radii:
$(i)$ $O, N, F, B, Be, Li, C$
$(ii)$ $P, S, Mg, Na, Al, Si, Cl$
$(iii)$ $K, Na, Li, Cs, Rb$
$(iv)$ $Cl, F, I, At, Br$

Which of the following is the correct increasing order of ionic radii for $N^{3-}$,$Na^+$,$F^-$,$O^{2-}$,and $Mg^{2+}$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module