$2 \times 10^{8}$ atoms of carbon are arranged side by side. Calculate the radius of a carbon atom if the length of this arrangement is $2.4 \, cm$.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
Length of the given arrangement $= 2.4 \, cm = 2.4 \times 10^{-2} \, m$.
Number of carbon atoms present $= 2 \times 10^{8}$.
Diameter of a carbon atom $= \frac{\text{Total length}}{\text{Number of atoms}} = \frac{2.4 \times 10^{-2} \, m}{2 \times 10^{8}} = 1.2 \times 10^{-10} \, m$.
Radius of a carbon atom $= \frac{\text{Diameter}}{2} = \frac{1.2 \times 10^{-10} \, m}{2} = 6.0 \times 10^{-11} \, m$.

Explore More

Similar Questions

What do you mean by significant figures?

How many significant figures are present in the following?
$(i)$ $0.0025$
$(ii)$ $208$
$(iii)$ $5005$
$(iv)$ $126.000$
$(v)$ $500.0$
$(vi)$ $2.0034$

Significant figures in $0.00051$ are

What is the $SI$ unit of mass? How is it defined?

Difficult
View Solution

Round up the following numbers to three significant figures:
$(i)$ $34.216$
$(ii)$ $10.4107$
$(iii)$ $0.04597$
$(iv)$ $2808$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo