20 volume H_2O_2 solution has a strength of a | vedclass

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(B) The decomposition of $H_2O_2$ is given by: $2H_2O_2 \rightarrow 2H_2O + O_2$.$68 \, g$ of $H_2O_2$ produces $22.4 \, L$ of $O_2$ at $N.T.P$.Theref

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(B) The decomposition of $H_2O_2$ is given by: $2H_2O_2 ightarrow 2H_2O + O_2$.$68 \, g$ of $H_2O_2$ produces $22.4 \, L$ of $O_2$ at $N.T.P$.Therefore,$1 \, L$ of $O_2$ is produced by $\frac{68}{22.4} \, g$ of $H_2O_2$.For a $20$ volume solution,$1 \, L$ of $H_2O_2$ solution produces $20 \, L$ of $O_2$.Mass of $H_2O_2$ in $1 \, L$ of solution $= \frac{68}{22.4} 	imes 20 \approx 60.71 \, g$.Strength in percentage $(\% \, w/v) = \frac{	ext{mass of solute in } g}{	ext{volume of solution in } mL} 	imes 100$.Strength $= \frac{60.71 \, g}{1000 \, mL} 	imes 100 \approx 6.07 \%$.Thus,the strength is approximately $6 \%$.

$20$ volume $H_2O_2$ solution has a strength of about $........... \%$

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