Na_2CO_3 can be manufactured by Solvay's proc | vedclass

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(C) In the Solvay process,the key step is the precipitation of $NaHCO_3$ by the reaction of $NH_4HCO_3$ with $NaCl$ solution. $NaCl + NH_4HCO_3 \right

Vedclass · Accepted Answer

$KHCO_3$ is more soluble than $NaHCO_3$.

Vedclass · Answer

(C) In the Solvay process,the key step is the precipitation of $NaHCO_3$ by the reaction of $NH_4HCO_3$ with $NaCl$ solution. $NaCl + NH_4HCO_3 \rightarrow NaHCO_3 \downarrow + NH_4Cl$. $NaHCO_3$ is relatively less soluble and precipitates out,which can then be heated to form $Na_2CO_3$. However,in the case of potassium,$KHCO_3$ is much more soluble in water than $NaHCO_3$. Therefore,$KHCO_3$ does not precipitate out when $CO_2$ is passed through a solution of $KCl$ and $NH_3$,making it impossible to isolate $KHCO_3$ by this method.

$Na_2CO_3$ can be manufactured by Solvay's process,but $K_2CO_3$ cannot be prepared by this method because:

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