Four forces act on a stationary particle at t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The resultant force $\overrightarrow{F}$ is the vector sum of all individual forces acting on the particle.$\overrightarrow{F} = \overrightarrow{F

Vedclass · Accepted Answer

$xz$-plane

Vedclass · Answer

(C) The resultant force $\overrightarrow{F}$ is the vector sum of all individual forces acting on the particle.$\overrightarrow{F} = \overrightarrow{F_1} + \overrightarrow{F_2} + \overrightarrow{F_3} + \overrightarrow{F_4}$$\overrightarrow{F} = (3\hat{i} - \hat{j} + 9\hat{k}) + (2\hat{i} - 2\hat{j} + 16\hat{k}) + (9\hat{i} + \hat{j} + 18\hat{k}) + (\hat{i} + 2\hat{j} - 18\hat{k})$Summing the components:$x$-component: $3 + 2 + 9 + 1 = 15$$y$-component: $-1 - 2 + 1 + 2 = 0$$z$-component: $9 + 16 + 18 - 18 = 25$Thus,$\overrightarrow{F} = 15\hat{i} + 0\hat{j} + 25\hat{k}$.Since the $y$-component is $0$,the particle will move in the plane where $y = 0$,which is the $xz$-plane.

Similar Questions

The vectors $(\vec{A} + \vec{B})$ and $(\vec{A} - \vec{B})$ are perpendicular to each other. This is possible under the condition:

The figure shows three vectors $\vec{a}, \vec{b}$ and $\vec{c}$,where $R$ is the midpoint of $PQ$. Which of the following relations is correct?

If the magnitude of the sum of two vectors is equal to the magnitude of the difference of two vectors,then the angle between them is: (in $^{\circ}$)

If the resultant of two forces has a magnitude smaller than the magnitude of the larger force,the two forces must be

Vedclass Test Series

Exam Paper Generator

Online Exam Module