Define the universal gravitational constant $(G)$.
(N/A) According to Newton's law of gravitation,the force between two masses is given by $F = \frac{G m_{1} m_{2}}{r^{2}}$.
If we take $m_{1} = 1 \ kg$,$m_{2} = 1 \ kg$,and $r = 1 \ m$,then $F = G$.
Therefore,the universal gravitational constant is defined as the gravitational force of attraction between two bodies of unit mass separated by a unit distance.
If we take $m_{1} = 1 \ kg$,$m_{2} = 1 \ kg$,and $r = 1 \ m$,then $F = G$.
Therefore,the universal gravitational constant is defined as the gravitational force of attraction between two bodies of unit mass separated by a unit distance.
Explore More
Similar Questions
$A$ uniform sphere of mass $M$ and radius $R$ is surrounded by a concentric spherical shell of the same mass but radius $2R$. $A$ point mass $m$ is kept at a distance $x$ $(R < x < 2R)$ in the region bounded by the spheres as shown in the figure. The net gravitational force on the particle is:
Easy
View SolutionThe atmosphere is held to the earth by
Three particles each of mass $M$ are placed at the three corners of an equilateral triangle of side $l$. What is the gravitational force due to this system of particles on another particle of mass $m$ placed at the midpoint of any side?
Difficult
View SolutionThe mass of the Moon is approximately $10\%$ of the mass of the Earth. What will be the gravitational force exerted by the Moon on the Earth compared to the gravitational force exerted by the Earth on the Moon?
Easy
View SolutionThe long-range force experienced by a neutral particle with a finite mass is:
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo