Explain the structure of the O_2 molecule. | vedclass

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Question

(A) According to Molecular Orbital Theory $(MOT)$,the electronic configuration of the $O_2$ molecule ($16$ electrons) is: $\sigma 1s^2, \sigma^* 1s^2,

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Paramagnetic with a bond order of $2$.

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(A) According to Molecular Orbital Theory $(MOT)$,the electronic configuration of the $O_2$ molecule ($16$ electrons) is: $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^1 = \pi^* 2p_y^1$. Since there are two unpaired electrons in the $\pi^*$ antibonding orbitals,the $O_2$ molecule is paramagnetic. The bond order is calculated as: $	ext{Bond Order} = \frac{N_b - N_a}{2} = \frac{10 - 6}{2} = 2$.

Explain the structure of the $O_2$ molecule.

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