In an ionic oxide,the oxide anions form an hc | vedclass

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(A) Let the number of oxide ions $(O^{2-})$ in the $hcp$ arrangement be $N$. Since the oxide ions form an $hcp$ lattice,the number of octahedral voids

Vedclass · Accepted Answer

$M_2O_3$

Vedclass · Answer

(A) Let the number of oxide ions $(O^{2-})$ in the $hcp$ arrangement be $N$. Since the oxide ions form an $hcp$ lattice,the number of octahedral voids is equal to $N$. The metal cations $(M^{n+})$ occupy $\frac{2}{3}$ of the octahedral voids,so the number of metal cations is $\frac{2}{3}N$. The ratio of $M : O$ is $\frac{2}{3}N : N$,which simplifies to $2 : 3$. Therefore,the formula of the oxide is $M_2O_3$.

In an ionic oxide,the oxide anions form an $hcp$ arrangement,while the metal cations occupy $\frac{2}{3}$ of the octahedral voids. Determine the formula of this oxide.

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